Download Computer Science Logic: 21st International Workshop, CSL by Samson Abramsky (auth.), Jacques Duparc, Thomas A. Henzinger PDF

By Samson Abramsky (auth.), Jacques Duparc, Thomas A. Henzinger (eds.)

This e-book constitutes the refereed complaints of the twenty first overseas Workshop on laptop technology common sense, CSL 2007, held because the sixteenth Annual convention of the EACSL in Lausanne, Switzerland in September 2007.

The 36 revised complete papers offered including the abstracts of six invited lectures have been rigorously reviewed and chosen from 116 submissions. The papers are geared up in topical sections on good judgment and video games, expressiveness, video games and bushes, common sense and deduction, lambda calculus, finite version concept, linear good judgment, evidence conception, and online game semantics.

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Read or Download Computer Science Logic: 21st International Workshop, CSL 2007, 16th Annual Conference of the EACSL, Lausanne, Switzerland, September 11-15, 2007. Proceedings PDF

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Extra resources for Computer Science Logic: 21st International Workshop, CSL 2007, 16th Annual Conference of the EACSL, Lausanne, Switzerland, September 11-15, 2007. Proceedings

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Static Analysis by Policy Iteration on Relational Domains. In: De Nicola, R. ) ESOP 2007. LNCS, vol. 4421, pp. 237–252. Springer, Heidelberg (2007) 11.

X := Ax + b]]TT c)i· = Ti· b + LP T,(Ti· A)T (c) T c and c := . −A b 3. ]]TT c ≤ forget T,k + c. ]]TT c = forget T,k + c whenever c is open. Thereby the vector forget T,k ∈ TT is defined by 2. ([[Ax + b ≥ 0]]TT c)i· = LP A ,Ti·T (c ) where A := (forget T,k )i· = ∞ if Ti·k = 0 0 if Ti·k = 0. Note that the post operator in [20] combines an affine assignment and a guard. In order to compute the abstract semantics VTT of G over TT , we rely on our methods for 36 T. Gawlitza and H. Seidl systems of rational equations presented in section 3.

Then we obtain systems E1 and E2 from E1 and E2 by replacing all occurrences of the 1 variable xi in right-hand sides with ∞ and 1−c · e, respectively. First consider the case c < 1. Since μ is consistent we get that μ (xi ) > −∞. 1 · e]]μ , ∞}. If μ (xi ) = ∞, we conclude that, since Dμ (E1 ) ⊆ Thus, μ (xi ) ∈ {[[ 1−c Dμ (E1 ) ⊆ Dμ (E), μ is a consistent solution of E1 . Since μ is a pre-solution of E1 and E1 has at least one variable less in right-hand sides than E, we get μ ≤ μ by induction 1 · e]]μ , we conclude that since Dμ (E2 ) ⊆ Dμ (E2 ) ⊆ hypothesis.

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